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55311487547 = 98429561943
BaseRepresentation
bin110011100000110100…
…100101001000111011
312021202202022200202212
4303200310211020323
51401234220100142
641224301045335
73665445613121
oct634064451073
9167682280685
1055311487547
1121503990288
12a87785684b
1352a62bc074
142969d15911
15168ad28d82
hexce0d2523b

55311487547 has 4 divisors (see below), whose sum is σ = 55312147920. Its totient is φ = 55310827176.

The previous prime is 55311487519. The next prime is 55311487571. The reversal of 55311487547 is 74578411355.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55311487547 - 210 = 55311486523 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55311487495 and 55311487504.

It is not an unprimeable number, because it can be changed into a prime (55311487247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 182543 + ... + 379400.

It is an arithmetic number, because the mean of its divisors is an integer number (13828036980).

Almost surely, 255311487547 is an apocalyptic number.

55311487547 is a deficient number, since it is larger than the sum of its proper divisors (660373).

55311487547 is an equidigital number, since it uses as much as digits as its factorization.

55311487547 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 660372.

The product of its digits is 2352000, while the sum is 50.

The spelling of 55311487547 in words is "fifty-five billion, three hundred eleven million, four hundred eighty-seven thousand, five hundred forty-seven".

Divisors: 1 98429 561943 55311487547