Base | Representation |
---|---|
bin | 10000000110010010011… |
… | …01010011000011010101 |
3 | 1221212201200112121000111 |
4 | 20003021031103003111 |
5 | 33030303132121323 |
6 | 1102034412043021 |
7 | 54651054226546 |
oct | 10031115230325 |
9 | 1855650477014 |
10 | 553131520213 |
11 | 1a3644360a88 |
12 | 8b24a763471 |
13 | 4021090072c |
14 | 1cab37d44cd |
15 | e5c539ac0d |
hex | 80c93530d5 |
553131520213 has 8 divisors (see below), whose sum is σ = 597083500800. Its totient is φ = 510838105008.
The previous prime is 553131520163. The next prime is 553131520217. The reversal of 553131520213 is 312025131355.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 553131520213 - 237 = 415692566741 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (553131520217) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 414640653 + ... + 414641986.
It is an arithmetic number, because the mean of its divisors is an integer number (74635437600).
Almost surely, 2553131520213 is an apocalyptic number.
It is an amenable number.
553131520213 is a deficient number, since it is larger than the sum of its proper divisors (43951980587).
553131520213 is a wasteful number, since it uses less digits than its factorization.
553131520213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 829282691.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 553131520213 its reverse (312025131355), we get a palindrome (865156651568).
The spelling of 553131520213 in words is "five hundred fifty-three billion, one hundred thirty-one million, five hundred twenty thousand, two hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •