Base | Representation |
---|---|
bin | 11001001001110111010111… |
… | …10001000001001000100111 |
3 | 21020212000111200221002212011 |
4 | 30210323223301001020213 |
5 | 24222233141322131401 |
6 | 313351052330335051 |
7 | 14436225655045102 |
oct | 1444735361011047 |
9 | 236760450832764 |
10 | 55314544333351 |
11 | 16696848257856 |
12 | 62543b4b8a487 |
13 | 24b31a692cb44 |
14 | d933499c1739 |
15 | 65dcd1847451 |
hex | 324eebc41227 |
55314544333351 has 4 divisors (see below), whose sum is σ = 55315371954304. Its totient is φ = 55313716712400.
The previous prime is 55314544333343. The next prime is 55314544333357. The reversal of 55314544333351 is 15333344541355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55314544333351 - 23 = 55314544333343 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55314544333295 and 55314544333304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55314544333357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 413710215 + ... + 413843896.
It is an arithmetic number, because the mean of its divisors is an integer number (13828842988576).
Almost surely, 255314544333351 is an apocalyptic number.
55314544333351 is a deficient number, since it is larger than the sum of its proper divisors (827620953).
55314544333351 is an equidigital number, since it uses as much as digits as its factorization.
55314544333351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 827620952.
The product of its digits is 9720000, while the sum is 49.
The spelling of 55314544333351 in words is "fifty-five trillion, three hundred fourteen billion, five hundred forty-four million, three hundred thirty-three thousand, three hundred fifty-one".
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