Base | Representation |
---|---|
bin | 100000111110011… |
… | …000001111001001 |
3 | 1102112222122102221 |
4 | 200332120033021 |
5 | 2113111114423 |
6 | 130521254041 |
7 | 16465214242 |
oct | 4076301711 |
9 | 1375878387 |
10 | 553223113 |
11 | 264309793 |
12 | 135334321 |
13 | 8a7cb571 |
14 | 5368bcc9 |
15 | 3387ce5d |
hex | 20f983c9 |
553223113 has 4 divisors (see below), whose sum is σ = 556089748. Its totient is φ = 550356480.
The previous prime is 553223101. The next prime is 553223123. The reversal of 553223113 is 311322355.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311322355 = 5 ⋅62264471.
It can be written as a sum of positive squares in 2 ways, for example, as 230948809 + 322274304 = 15197^2 + 17952^2 .
It is a cyclic number.
It is not a de Polignac number, because 553223113 - 25 = 553223081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (553223123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1433028 + ... + 1433413.
It is an arithmetic number, because the mean of its divisors is an integer number (139022437).
Almost surely, 2553223113 is an apocalyptic number.
It is an amenable number.
553223113 is a deficient number, since it is larger than the sum of its proper divisors (2866635).
553223113 is a wasteful number, since it uses less digits than its factorization.
553223113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2866634.
The product of its digits is 2700, while the sum is 25.
The square root of 553223113 is about 23520.6954191410. The cubic root of 553223113 is about 820.9186180505.
Adding to 553223113 its reverse (311322355), we get a palindrome (864545468).
The spelling of 553223113 in words is "five hundred fifty-three million, two hundred twenty-three thousand, one hundred thirteen".
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