Base | Representation |
---|---|
bin | 10000000110011110110… |
… | …01101100101011100101 |
3 | 1221212222221001222020011 |
4 | 20003033121230223211 |
5 | 33031011232343323 |
6 | 1102053003210221 |
7 | 54653455413040 |
oct | 10031731545345 |
9 | 1855887058204 |
10 | 553235434213 |
11 | 1a3697a86120 |
12 | 8b279516971 |
13 | 402292b48c7 |
14 | 1cac3523c57 |
15 | e5ce57520d |
hex | 80cf66cae5 |
553235434213 has 16 divisors (see below), whose sum is σ = 719737122816. Its totient is φ = 412349390640.
The previous prime is 553235434201. The next prime is 553235434217. The reversal of 553235434213 is 312434532355.
553235434213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 553235434213 - 217 = 553235303141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (553235434217) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 156191181 + ... + 156194722.
It is an arithmetic number, because the mean of its divisors is an integer number (44983570176).
Almost surely, 2553235434213 is an apocalyptic number.
It is an amenable number.
553235434213 is a deficient number, since it is larger than the sum of its proper divisors (166501688603).
553235434213 is a wasteful number, since it uses less digits than its factorization.
553235434213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 312385944.
The product of its digits is 648000, while the sum is 40.
Adding to 553235434213 its reverse (312434532355), we get a palindrome (865669966568).
The spelling of 553235434213 in words is "five hundred fifty-three billion, two hundred thirty-five million, four hundred thirty-four thousand, two hundred thirteen".
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