Base | Representation |
---|---|
bin | 101000010000100100110… |
… | …0100001100101011101111 |
3 | 201120222000212212011122222 |
4 | 1100201021210030223233 |
5 | 1211123343414300101 |
6 | 15433521152225555 |
7 | 1110520444602461 |
oct | 120411144145357 |
9 | 21528025764588 |
10 | 5533152103151 |
11 | 1843662127812 |
12 | 75444153b2bb |
13 | 311a0a64590a |
14 | 151b3d8d2131 |
15 | 98de3a6a01b |
hex | 5084990caef |
5533152103151 has 4 divisors (see below), whose sum is σ = 5711640880704. Its totient is φ = 5354663325600.
The previous prime is 5533152103121. The next prime is 5533152103163. The reversal of 5533152103151 is 1513012513355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5533152103151 - 214 = 5533152086767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5533152103121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89244388730 + ... + 89244388791.
It is an arithmetic number, because the mean of its divisors is an integer number (1427910220176).
Almost surely, 25533152103151 is an apocalyptic number.
5533152103151 is a deficient number, since it is larger than the sum of its proper divisors (178488777553).
5533152103151 is a wasteful number, since it uses less digits than its factorization.
5533152103151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 178488777552.
The product of its (nonzero) digits is 33750, while the sum is 35.
The spelling of 5533152103151 in words is "five trillion, five hundred thirty-three billion, one hundred fifty-two million, one hundred three thousand, one hundred fifty-one".
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