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55333264031 = 311784944001
BaseRepresentation
bin110011100010000111…
…101001101010011111
312021211021022001111022
4303202013221222133
51401310303422111
641230355514355
73666131661323
oct634207515237
9167737261438
1055333264031
1121515204281
12a882bb89bb
1352aa974c66
14296cb83983
15168cbcb2db
hexce21e9a9f

55333264031 has 4 divisors (see below), whose sum is σ = 57118208064. Its totient is φ = 53548320000.

The previous prime is 55333263971. The next prime is 55333264069. The reversal of 55333264031 is 13046233355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55333264031 is a prime.

It is a super-2 number, since 2×553332640312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55333263982 and 55333264000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55333264531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 892471970 + ... + 892472031.

It is an arithmetic number, because the mean of its divisors is an integer number (14279552016).

Almost surely, 255333264031 is an apocalyptic number.

55333264031 is a deficient number, since it is larger than the sum of its proper divisors (1784944033).

55333264031 is a wasteful number, since it uses less digits than its factorization.

55333264031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1784944032.

The product of its (nonzero) digits is 97200, while the sum is 35.

Adding to 55333264031 its reverse (13046233355), we get a palindrome (68379497386).

The spelling of 55333264031 in words is "fifty-five billion, three hundred thirty-three million, two hundred sixty-four thousand, thirty-one".

Divisors: 1 31 1784944001 55333264031