Base | Representation |
---|---|
bin | 11001001010011011101010… |
… | …11000100010111110011011 |
3 | 21020220212210220101011002101 |
4 | 30211031311120202332123 |
5 | 24223043044424341410 |
6 | 313404034233144231 |
7 | 14440515631253443 |
oct | 1445156530427633 |
9 | 236825726334071 |
10 | 55334033043355 |
11 | 166a4039109060 |
12 | 625813385b077 |
13 | 24b4c913cb901 |
14 | d94278013123 |
15 | 65e572769d3a |
hex | 325375622f9b |
55334033043355 has 8 divisors (see below), whose sum is σ = 72437279620464. Its totient is φ = 40242933122400.
The previous prime is 55334033043269. The next prime is 55334033043361.
55334033043355 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55334033043355 - 239 = 54784277229467 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 503036663976 + ... + 503036664085.
It is an arithmetic number, because the mean of its divisors is an integer number (9054659952558).
Almost surely, 255334033043355 is an apocalyptic number.
55334033043355 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55334033043355 is a deficient number, since it is larger than the sum of its proper divisors (17103246577109).
55334033043355 is a wasteful number, since it uses less digits than its factorization.
55334033043355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1006073328077.
The product of its (nonzero) digits is 7290000, while the sum is 46.
It can be divided in two parts, 5533403 and 3043355, that added together give a palindrome (8576758).
The spelling of 55334033043355 in words is "fifty-five trillion, three hundred thirty-four billion, thirty-three million, forty-three thousand, three hundred fifty-five".
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