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55334033043361 is a prime number
BaseRepresentation
bin11001001010011011101010…
…11000100010111110100001
321020220212210220101011002121
430211031311120202332201
524223043044424341421
6313404034233144241
714440515631253452
oct1445156530427641
9236825726334077
1055334033043361
11166a4039109066
12625813385b081
1324b4c913cb907
14d94278013129
1565e572769d41
hex325375622fa1

55334033043361 has 2 divisors, whose sum is σ = 55334033043362. Its totient is φ = 55334033043360.

The previous prime is 55334033043269. The next prime is 55334033043371. The reversal of 55334033043361 is 16334033043355.

55334033043361 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 45410077690000 + 9923955353361 = 6738700^2 + 3150231^2 .

It is a cyclic number.

It is not a de Polignac number, because 55334033043361 - 215 = 55334033010593 is a prime.

It is not a weakly prime, because it can be changed into another prime (55334033043371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27667016521680 + 27667016521681.

It is an arithmetic number, because the mean of its divisors is an integer number (27667016521681).

Almost surely, 255334033043361 is an apocalyptic number.

It is an amenable number.

55334033043361 is a deficient number, since it is larger than the sum of its proper divisors (1).

55334033043361 is an equidigital number, since it uses as much as digits as its factorization.

55334033043361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1749600, while the sum is 43.

The spelling of 55334033043361 in words is "fifty-five trillion, three hundred thirty-four billion, thirty-three million, forty-three thousand, three hundred sixty-one".