Base | Representation |
---|---|
bin | 111110111010001001101100… |
… | …0101100001110110111011111 |
3 | 2200120020202011211211021211111 |
4 | 1331310103120230032313133 |
5 | 1040012041341224140333 |
6 | 5240513255554002451 |
7 | 224361135613055440 |
oct | 17564233054166737 |
9 | 2616222154737744 |
10 | 553350042021343 |
11 | 150350486a08166 |
12 | 5208ab41576427 |
13 | 1a99b8ba108a78 |
14 | 9a903dbc0b2c7 |
15 | 43e8d878564cd |
hex | 1f744d8b0eddf |
553350042021343 has 16 divisors (see below), whose sum is σ = 639576407004480. Its totient is φ = 468918945792000.
The previous prime is 553350042021313. The next prime is 553350042021349. The reversal of 553350042021343 is 343120240053355.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-553350042021343 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 553350042021296 and 553350042021305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (553350042021349) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43488258 + ... + 54753343.
It is an arithmetic number, because the mean of its divisors is an integer number (39973525437780).
Almost surely, 2553350042021343 is an apocalyptic number.
553350042021343 is a deficient number, since it is larger than the sum of its proper divisors (86226364983137).
553350042021343 is an equidigital number, since it uses as much as digits as its factorization.
553350042021343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98250738.
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 553350042021343 its reverse (343120240053355), we get a palindrome (896470282074698).
The spelling of 553350042021343 in words is "five hundred fifty-three trillion, three hundred fifty billion, forty-two million, twenty-one thousand, three hundred forty-three".
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