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5533542135103 = 33191667231737
BaseRepresentation
bin101000010000110000011…
…0100000011010100111111
3201121000001001202211220211
41100201200310003110333
51211130143241310403
615434024004053251
71110533222040043
oct120414064032477
921530031684824
105533542135103
111843842304574
12754530094227
13311a703a7058
14151b79620023
1598e17e1006d
hex50860d0353f

5533542135103 has 4 divisors (see below), whose sum is σ = 5535209370160. Its totient is φ = 5531874900048.

The previous prime is 5533542135089. The next prime is 5533542135139. The reversal of 5533542135103 is 3015312453355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5533542135103 - 29 = 5533542134591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5533542105103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 833612550 + ... + 833619187.

It is an arithmetic number, because the mean of its divisors is an integer number (1383802342540).

Almost surely, 25533542135103 is an apocalyptic number.

5533542135103 is a deficient number, since it is larger than the sum of its proper divisors (1667235057).

5533542135103 is a wasteful number, since it uses less digits than its factorization.

5533542135103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1667235056.

The product of its (nonzero) digits is 405000, while the sum is 40.

Adding to 5533542135103 its reverse (3015312453355), we get a palindrome (8548854588458).

The spelling of 5533542135103 in words is "five trillion, five hundred thirty-three billion, five hundred forty-two million, one hundred thirty-five thousand, one hundred three".

Divisors: 1 3319 1667231737 5533542135103