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5534001104000 = 27531920538867
BaseRepresentation
bin101000010000111110000…
…1010111000010010000000
3201121001020001101212212212
41100201330022320102000
51211132113240312000
615434141321241252
71110550464152555
oct120417412702200
921531201355785
105534001104000
111843a58396706
12754639933228
13311b144c4195
14151bc0574a2c
1598e43370c35
hex5087c2b8480

5534001104000 has 256 divisors, whose sum is σ = 14491752163200. Its totient is φ = 2095837286400.

The previous prime is 5534001103993. The next prime is 5534001104069. The reversal of 5534001104000 is 4011004355.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 624107567 + ... + 624116433.

Almost surely, 25534001104000 is an apocalyptic number.

5534001104000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5534001104000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7245876081600).

5534001104000 is an abundant number, since it is smaller than the sum of its proper divisors (8957751059200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5534001104000 is a wasteful number, since it uses less digits than its factorization.

5534001104000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10968 (or 10946 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 5534001104000 its reverse (4011004355), we get a palindrome (5538012108355).

The spelling of 5534001104000 in words is "five trillion, five hundred thirty-four billion, one million, one hundred four thousand".