55340433 has 6 divisors (see below), whose sum is σ = 79936194. Its totient is φ = 36893616.

The previous prime is 55340387. The next prime is 55340437. The reversal of 55340433 is 33404355.

It is a happy number.

55340433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 54508689 + 831744 = 7383^2 + 912^2 .

It is not a de Polignac number, because 55340433 - 2²² = 51146129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55340397 and 55340406.

It is not an unprimeable number, because it can be changed into a prime (55340437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3074460 + ... + 3074477.

It is an arithmetic number, because the mean of its divisors is an integer number (13322699).

Almost surely, 2^55340433 is an apocalyptic number.

It is an amenable number.

55340433 is a deficient number, since it is larger than the sum of its proper divisors (24595761).

55340433 is a wasteful number, since it uses less digits than its factorization.

55340433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6148943 (or 6148940 counting only the distinct ones).

The product of its (nonzero) digits is 10800, while the sum is 27.

The square root of 55340433 is about 7439.1150683398. The cubic root of 55340433 is about 381.0782694098.

Adding to 55340433 its sum of digits (27), we get a triangular number (55340460 = T₁₀₅₂₀).

Adding to 55340433 its reverse (33404355), we get a palindrome (88744788).

The spelling of 55340433 in words is "fifty-five million, three hundred forty thousand, four hundred thirty-three".