553434434503 has 4 divisors (see below), whose sum is σ = 568392121960. Its totient is φ = 538476747048.

The previous prime is 553434434471. The next prime is 553434434533. The reversal of 553434434503 is 305434434355.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 553434434503 - 2⁵ = 553434434471 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 553434434503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (553434434533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7478843673 + ... + 7478843746.

It is an arithmetic number, because the mean of its divisors is an integer number (142098030490).

Almost surely, 2^553434434503 is an apocalyptic number.

553434434503 is a deficient number, since it is larger than the sum of its proper divisors (14957687457).

553434434503 is a wasteful number, since it uses less digits than its factorization.

553434434503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14957687456.

The product of its (nonzero) digits is 2592000, while the sum is 43.

Adding to 553434434503 its reverse (305434434355), we get a palindrome (858868868858).

The spelling of 553434434503 in words is "five hundred fifty-three billion, four hundred thirty-four million, four hundred thirty-four thousand, five hundred three".