Base | Representation |
---|---|
bin | 11001001010110011110111… |
… | …00111010001110111100111 |
3 | 21020222010100011021102111111 |
4 | 30211121323213101313213 |
5 | 24223301200223030011 |
6 | 313414023205445451 |
7 | 14441455545465013 |
oct | 1445317347216747 |
9 | 236863304242444 |
10 | 55347022470631 |
11 | 166a95a4322021 |
12 | 625a759a10887 |
13 | 24b628153b158 |
14 | d94b4b1c9543 |
15 | 65ea82cce121 |
hex | 32567b9d1de7 |
55347022470631 has 4 divisors (see below), whose sum is σ = 55347043533264. Its totient is φ = 55347001408000.
The previous prime is 55347022470629. The next prime is 55347022470689. The reversal of 55347022470631 is 13607422074355.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55347022470631 - 21 = 55347022470629 is a prime.
It is a super-2 number, since 2×553470224706312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55347023470631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5915290 + ... + 12069991.
It is an arithmetic number, because the mean of its divisors is an integer number (13836760883316).
Almost surely, 255347022470631 is an apocalyptic number.
55347022470631 is a deficient number, since it is larger than the sum of its proper divisors (21062633).
55347022470631 is a wasteful number, since it uses less digits than its factorization.
55347022470631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21062632.
The product of its (nonzero) digits is 4233600, while the sum is 49.
The spelling of 55347022470631 in words is "fifty-five trillion, three hundred forty-seven billion, twenty-two million, four hundred seventy thousand, six hundred thirty-one".
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