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553637514133 = 1150330683103
BaseRepresentation
bin10000000111001110101…
…11100000101110010101
31221221000221122202012001
420003213113200232111
533032322200423013
61102200525155301
754666440136514
oct10034727405625
91857027582161
10553637514133
111a3883a41780
128b3700bbb31
13402916a3b12
141cb20aaa67b
15e6049e9ddd
hex80e75e0b95

553637514133 has 4 divisors (see below), whose sum is σ = 603968197248. Its totient is φ = 503306831020.

The previous prime is 553637514107. The next prime is 553637514137. The reversal of 553637514133 is 331415736355.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-553637514133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (553637514137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25165341541 + ... + 25165341562.

It is an arithmetic number, because the mean of its divisors is an integer number (150992049312).

Almost surely, 2553637514133 is an apocalyptic number.

It is an amenable number.

553637514133 is a deficient number, since it is larger than the sum of its proper divisors (50330683115).

553637514133 is a wasteful number, since it uses less digits than its factorization.

553637514133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50330683114.

The product of its digits is 1701000, while the sum is 46.

The spelling of 553637514133 in words is "five hundred fifty-three billion, six hundred thirty-seven million, five hundred fourteen thousand, one hundred thirty-three".

Divisors: 1 11 50330683103 553637514133