Base | Representation |
---|---|
bin | 110011100100100001… |
… | …001010100111101101 |
3 | 12021221002000121112121 |
4 | 303210201022213231 |
5 | 1401401104211203 |
6 | 41234354232541 |
7 | 4000131021034 |
oct | 634441124755 |
9 | 167832017477 |
10 | 55373507053 |
11 | 215359a0477 |
12 | a894585751 |
13 | 52b60c52b7 |
14 | 297425b71b |
15 | 16914ca0bd |
hex | ce484a9ed |
55373507053 has 4 divisors (see below), whose sum is σ = 57159749248. Its totient is φ = 53587264860.
The previous prime is 55373507047. The next prime is 55373507081. The reversal of 55373507053 is 35070537355.
55373507053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55373507053 - 29 = 55373506541 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55373502053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893121051 + ... + 893121112.
It is an arithmetic number, because the mean of its divisors is an integer number (14289937312).
Almost surely, 255373507053 is an apocalyptic number.
It is an amenable number.
55373507053 is a deficient number, since it is larger than the sum of its proper divisors (1786242195).
55373507053 is a wasteful number, since it uses less digits than its factorization.
55373507053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1786242194.
The product of its (nonzero) digits is 826875, while the sum is 43.
The spelling of 55373507053 in words is "fifty-five billion, three hundred seventy-three million, five hundred seven thousand, fifty-three".
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