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553891273740 = 2233571033141851
BaseRepresentation
bin10000000111101100111…
…11100001110000001100
31221221200122011001221000
420003312133201300030
533033332131224430
61102242032140300
755005641100450
oct10036637416014
91857618131830
10553891273740
111a39a4203062
128b421097690
134030213182c
141cb46684660
15e61be22e60
hex80f67e1c0c

553891273740 has 192 divisors, whose sum is σ = 1971311569920. Its totient is φ = 126480268800.

The previous prime is 553891273729. The next prime is 553891273801. The reversal of 553891273740 is 47372198355.

553891273740 is a `hidden beast` number, since 553 + 8 + 9 + 12 + 7 + 3 + 74 + 0 = 666.

It is a super-2 number, since 2×5538912737402 (a number of 24 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3833815 + ... + 3975665.

It is an arithmetic number, because the mean of its divisors is an integer number (10267247760).

Almost surely, 2553891273740 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 553891273740, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (985655784960).

553891273740 is an abundant number, since it is smaller than the sum of its proper divisors (1417420296180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

553891273740 is a wasteful number, since it uses less digits than its factorization.

553891273740 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142909 (or 142901 counting only the distinct ones).

The product of its (nonzero) digits is 6350400, while the sum is 54.

The spelling of 553891273740 in words is "five hundred fifty-three billion, eight hundred ninety-one million, two hundred seventy-three thousand, seven hundred forty".