Base | Representation |
---|---|
bin | 110011100110001011… |
… | …001111100000100101 |
3 | 12022000000100100222011 |
4 | 303212023033200211 |
5 | 1401430214024331 |
6 | 41241230234221 |
7 | 4000616254612 |
oct | 634613174045 |
9 | 168000310864 |
10 | 55401314341 |
11 | 2154a6634aa |
12 | a8a1955971 |
13 | 52bbab0209 |
14 | 2977c19509 |
15 | 1693b6e3b1 |
hex | ce62cf825 |
55401314341 has 4 divisors (see below), whose sum is σ = 55410132672. Its totient is φ = 55392496012.
The previous prime is 55401314327. The next prime is 55401314347. The reversal of 55401314341 is 14341310455.
55401314341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55401314341 - 229 = 54864443429 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55401314347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4399735 + ... + 4412308.
It is an arithmetic number, because the mean of its divisors is an integer number (13852533168).
Almost surely, 255401314341 is an apocalyptic number.
It is an amenable number.
55401314341 is a deficient number, since it is larger than the sum of its proper divisors (8818331).
55401314341 is an equidigital number, since it uses as much as digits as its factorization.
55401314341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8818330.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 55401314341 its reverse (14341310455), we get a palindrome (69742624796).
The spelling of 55401314341 in words is "fifty-five billion, four hundred one million, three hundred fourteen thousand, three hundred forty-one".
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