Base | Representation |
---|---|
bin | 101000010100000110110… |
… | …1111011100011111010111 |
3 | 201121200121120201121012201 |
4 | 1100220031233130133113 |
5 | 1211234413004244421 |
6 | 15441214032025331 |
7 | 1111206442632343 |
oct | 120501557343727 |
9 | 21550546647181 |
10 | 5540738353111 |
11 | 18468a5398685 |
12 | 7559ba092247 |
13 | 312649241a10 |
14 | 15225d256623 |
15 | 991d9a87b91 |
hex | 50a0dbdc7d7 |
5540738353111 has 4 divisors (see below), whose sum is σ = 5966948995672. Its totient is φ = 5114527710552.
The previous prime is 5540738353079. The next prime is 5540738353217. The reversal of 5540738353111 is 1113538370455.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5540738353111 - 25 = 5540738353079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5540738351111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213105321261 + ... + 213105321286.
It is an arithmetic number, because the mean of its divisors is an integer number (1491737248918).
Almost surely, 25540738353111 is an apocalyptic number.
5540738353111 is a deficient number, since it is larger than the sum of its proper divisors (426210642561).
5540738353111 is a wasteful number, since it uses less digits than its factorization.
5540738353111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426210642560.
The product of its (nonzero) digits is 756000, while the sum is 46.
The spelling of 5540738353111 in words is "five trillion, five hundred forty billion, seven hundred thirty-eight million, three hundred fifty-three thousand, one hundred eleven".
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