Base | Representation |
---|---|
bin | 110011100110101100… |
… | …110000100011011001 |
3 | 12022000121212202020021 |
4 | 303212230300203121 |
5 | 1401434441203231 |
6 | 41242142430441 |
7 | 4001054040223 |
oct | 634654604331 |
9 | 168017782207 |
10 | 55410100441 |
11 | 21554614643 |
12 | a8a4892421 |
13 | 52c08683a7 |
14 | 2979065413 |
15 | 1694807811 |
hex | ce6b308d9 |
55410100441 has 8 divisors (see below), whose sum is σ = 60033926304. Its totient is φ = 50937875520.
The previous prime is 55410100433. The next prime is 55410100457. The reversal of 55410100441 is 14400101455.
55410100441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55410100441 - 23 = 55410100433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55410100541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37899475 + ... + 37900936.
It is an arithmetic number, because the mean of its divisors is an integer number (7504240788).
Almost surely, 255410100441 is an apocalyptic number.
It is an amenable number.
55410100441 is a deficient number, since it is larger than the sum of its proper divisors (4623825863).
55410100441 is a wasteful number, since it uses less digits than its factorization.
55410100441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75800471.
The product of its (nonzero) digits is 1600, while the sum is 25.
Adding to 55410100441 its reverse (14400101455), we get a palindrome (69810201896).
The spelling of 55410100441 in words is "fifty-five billion, four hundred ten million, one hundred thousand, four hundred forty-one".
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