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55414000101 = 318471333367
BaseRepresentation
bin110011100110111011…
…101000100111100101
312022000220012212120010
4303212323220213211
51401441441000401
641242402200433
74001132141415
oct634673504745
9168026185503
1055414000101
11215568384a9
12a8a6053119
1352c1602395
14297979c645
151694d27ed6
hexce6ee89e5

55414000101 has 4 divisors (see below), whose sum is σ = 73885333472. Its totient is φ = 36942666732.

The previous prime is 55414000087. The next prime is 55414000127. The reversal of 55414000101 is 10100041455.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 55414000101 - 27 = 55413999973 is a prime.

It is a super-2 number, since 2×554140001012 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (55414000171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9235666681 + ... + 9235666686.

It is an arithmetic number, because the mean of its divisors is an integer number (18471333368).

Almost surely, 255414000101 is an apocalyptic number.

It is an amenable number.

55414000101 is a deficient number, since it is larger than the sum of its proper divisors (18471333371).

55414000101 is a wasteful number, since it uses less digits than its factorization.

55414000101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18471333370.

The product of its (nonzero) digits is 400, while the sum is 21.

Adding to 55414000101 its reverse (10100041455), we get a palindrome (65514041556).

The spelling of 55414000101 in words is "fifty-five billion, four hundred fourteen million, one hundred one", and thus it is an aban number.

Divisors: 1 3 18471333367 55414000101