Base | Representation |
---|---|
bin | 11001001100110100111000… |
… | …11000101110011110110011 |
3 | 21021012202010122200221222210 |
4 | 30212122130120232132303 |
5 | 24230420031143434111 |
6 | 313505520515303203 |
7 | 14446460241061563 |
oct | 1446323430563663 |
9 | 237182118627883 |
10 | 55416291780531 |
11 | 16725a10012880 |
12 | 627006bbaab03 |
13 | 24bc97048c2a6 |
14 | d9823cb58da3 |
15 | 6617891a90a6 |
hex | 32669c62e7b3 |
55416291780531 has 32 divisors (see below), whose sum is σ = 88100145801216. Its totient is φ = 30590328384000.
The previous prime is 55416291780529. The next prime is 55416291780581. The reversal of 55416291780531 is 13508719261455.
It is not a de Polignac number, because 55416291780531 - 21 = 55416291780529 is a prime.
It is a super-2 number, since 2×554162917805312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (55416291780581) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1593228880 + ... + 1593263661.
It is an arithmetic number, because the mean of its divisors is an integer number (2753129556288).
It is a 1-persistent number, because it is pandigital, but 2⋅55416291780531 = 110832583561062 is not.
Almost surely, 255416291780531 is an apocalyptic number.
55416291780531 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
55416291780531 is a deficient number, since it is larger than the sum of its proper divisors (32683854020685).
55416291780531 is a wasteful number, since it uses less digits than its factorization.
55416291780531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3186492603.
The product of its (nonzero) digits is 9072000, while the sum is 57.
The spelling of 55416291780531 in words is "fifty-five trillion, four hundred sixteen billion, two hundred ninety-one million, seven hundred eighty thousand, five hundred thirty-one".
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