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55433030241 = 318477676747
BaseRepresentation
bin110011101000000100…
…001110101001100001
312022002020000201000010
4303220010032221201
51402011323431431
641244322115133
74001452661031
oct635004165141
9168066021003
1055433030241
1121566556096
12a8b04abaa9
1352c5536214
14297c1138c1
151696836846
hexce810ea61

55433030241 has 4 divisors (see below), whose sum is σ = 73910706992. Its totient is φ = 36955353492.

The previous prime is 55433030197. The next prime is 55433030327. The reversal of 55433030241 is 14203033455.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 55433030241 - 210 = 55433029217 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 55433030199 and 55433030208.

It is not an unprimeable number, because it can be changed into a prime (55433030141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9238838371 + ... + 9238838376.

It is an arithmetic number, because the mean of its divisors is an integer number (18477676748).

Almost surely, 255433030241 is an apocalyptic number.

It is an amenable number.

55433030241 is a deficient number, since it is larger than the sum of its proper divisors (18477676751).

55433030241 is a wasteful number, since it uses less digits than its factorization.

55433030241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18477676750.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 55433030241 its reverse (14203033455), we get a palindrome (69636063696).

The spelling of 55433030241 in words is "fifty-five billion, four hundred thirty-three million, thirty thousand, two hundred forty-one".

Divisors: 1 3 18477676747 55433030241