Base | Representation |
---|---|
bin | 101000010101010011010… |
… | …0110111000110111100101 |
3 | 201121221020022121101102011 |
4 | 1100222212212320313211 |
5 | 1211310141033232401 |
6 | 15442320325514221 |
7 | 1111330134161263 |
oct | 120524646706745 |
9 | 21557208541364 |
10 | 5543303024101 |
11 | 18479a1052987 |
12 | 7563b4b72971 |
13 | 31296769520b |
14 | 152423add433 |
15 | 992d9cda451 |
hex | 50aa69b8de5 |
5543303024101 has 8 divisors (see below), whose sum is σ = 5574368177280. Its totient is φ = 5512238948832.
The previous prime is 5543303024099. The next prime is 5543303024113. The reversal of 5543303024101 is 1014203033455.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5543303024101 - 21 = 5543303024099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5543303025101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11474041 + ... + 11947393.
It is an arithmetic number, because the mean of its divisors is an integer number (696796022160).
Almost surely, 25543303024101 is an apocalyptic number.
It is an amenable number.
5543303024101 is a deficient number, since it is larger than the sum of its proper divisors (31065153179).
5543303024101 is a wasteful number, since it uses less digits than its factorization.
5543303024101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 538955.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5543303024101 its reverse (1014203033455), we get a palindrome (6557506057556).
The spelling of 5543303024101 in words is "five trillion, five hundred forty-three billion, three hundred three million, twenty-four thousand, one hundred one".
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