Base | Representation |
---|---|
bin | 11001001101100101101101… |
… | …00101000101000101010111 |
3 | 21021022020210020000210112122 |
4 | 30212302312211011011113 |
5 | 24231332220230431411 |
6 | 313525533334410155 |
7 | 14451405601034360 |
oct | 1446626645050527 |
9 | 237266706023478 |
10 | 55442501030231 |
11 | 1673603a4a3017 |
12 | 627516550095b |
13 | 24c22893a8173 |
14 | d9960795cb67 |
15 | 6622c00e29db |
hex | 326cb6945157 |
55442501030231 has 4 divisors (see below), whose sum is σ = 63362858320272. Its totient is φ = 47522143740192.
The previous prime is 55442501030207. The next prime is 55442501030243. The reversal of 55442501030231 is 13203010524455.
55442501030231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55442501030231 - 238 = 55167623123287 is a prime.
It is a super-2 number, since 2×554425010302312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 55442501030191 and 55442501030200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55442501030291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3960178645010 + ... + 3960178645023.
It is an arithmetic number, because the mean of its divisors is an integer number (15840714580068).
Almost surely, 255442501030231 is an apocalyptic number.
55442501030231 is a deficient number, since it is larger than the sum of its proper divisors (7920357290041).
55442501030231 is an equidigital number, since it uses as much as digits as its factorization.
55442501030231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7920357290040.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 55442501030231 its reverse (13203010524455), we get a palindrome (68645511554686).
The spelling of 55442501030231 in words is "fifty-five trillion, four hundred forty-two billion, five hundred one million, thirty thousand, two hundred thirty-one".
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