Base | Representation |
---|---|
bin | 11001001101101110100010… |
… | …01000010000101010101111 |
3 | 21021022201000120220221021201 |
4 | 30212313101020100222233 |
5 | 24231421422301141011 |
6 | 313532035553510331 |
7 | 14451634221534064 |
oct | 1446672110205257 |
9 | 237281016827251 |
10 | 55447241427631 |
11 | 16738052308819 |
12 | 6276068b723a7 |
13 | 24c2863511641 |
14 | d99937364c6b |
15 | 66249b369cc1 |
hex | 326dd1210aaf |
55447241427631 has 4 divisors (see below), whose sum is σ = 56228188490064. Its totient is φ = 54666294365200.
The previous prime is 55447241427593. The next prime is 55447241427667. The reversal of 55447241427631 is 13672414274455.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55447241427631 - 27 = 55447241427503 is a prime.
It is a super-3 number, since 3×554472414276313 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55447241527631) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 390473531110 + ... + 390473531251.
It is an arithmetic number, because the mean of its divisors is an integer number (14057047122516).
Almost surely, 255447241427631 is an apocalyptic number.
55447241427631 is a deficient number, since it is larger than the sum of its proper divisors (780947062433).
55447241427631 is an equidigital number, since it uses as much as digits as its factorization.
55447241427631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 780947062432.
The product of its digits is 22579200, while the sum is 55.
The spelling of 55447241427631 in words is "fifty-five trillion, four hundred forty-seven billion, two hundred forty-one million, four hundred twenty-seven thousand, six hundred thirty-one".
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