Base | Representation |
---|---|
bin | 11001001111000010111100… |
… | …00011110101110011101111 |
3 | 21021111000222121101211001021 |
4 | 30213201132003311303233 |
5 | 24233142223203420310 |
6 | 314004532244155011 |
7 | 14455130154204112 |
oct | 1447413603656357 |
9 | 237430877354037 |
10 | 55492555529455 |
11 | 167552959aa150 |
12 | 62829b4698a67 |
13 | 24c6c0551a145 |
14 | d9bbd55d8579 |
15 | 66374e6505da |
hex | 32785e0f5cef |
55492555529455 has 16 divisors (see below), whose sum is σ = 72644997921408. Its totient is φ = 40358112228000.
The previous prime is 55492555529447. The next prime is 55492555529459.
55492555529455 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55492555529455 - 23 = 55492555529447 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55492555529459) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22832800 + ... + 25146010.
It is an arithmetic number, because the mean of its divisors is an integer number (4540312370088).
Almost surely, 255492555529455 is an apocalyptic number.
55492555529455 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55492555529455 is a deficient number, since it is larger than the sum of its proper divisors (17152442391953).
55492555529455 is a wasteful number, since it uses less digits than its factorization.
55492555529455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2749398.
The product of its digits is 2025000000, while the sum is 70.
The spelling of 55492555529455 in words is "fifty-five trillion, four hundred ninety-two billion, five hundred fifty-five million, five hundred twenty-nine thousand, four hundred fifty-five".
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