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5550060312437 = 31179034203627
BaseRepresentation
bin101000011000011100101…
…0111111001011101110101
3201122120200020122012101112
41100300321113321131311
51211413010414444222
615445355034004405
71111656445162334
oct120607127713565
921576606565345
105550060312437
11184a8493a16a3
1275777bb76705
133134a360ac94
141528a5319d1b
159958315ebe2
hex50c395f9775

5550060312437 has 4 divisors (see below), whose sum is σ = 5729094516096. Its totient is φ = 5371026108780.

The previous prime is 5550060312403. The next prime is 5550060312473. The reversal of 5550060312437 is 7342130600555.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5550060312437 - 210 = 5550060311413 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5550060312394 and 5550060312403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5550060312487) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89517101783 + ... + 89517101844.

It is an arithmetic number, because the mean of its divisors is an integer number (1432273629024).

Almost surely, 25550060312437 is an apocalyptic number.

It is an amenable number.

5550060312437 is a deficient number, since it is larger than the sum of its proper divisors (179034203659).

5550060312437 is a wasteful number, since it uses less digits than its factorization.

5550060312437 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 179034203658.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 5550060312437 in words is "five trillion, five hundred fifty billion, sixty million, three hundred twelve thousand, four hundred thirty-seven".

Divisors: 1 31 179034203627 5550060312437