Base | Representation |
---|---|
bin | 110011101111000000… |
… | …001000011111101101 |
3 | 12022101022222202011002 |
4 | 303233000020133231 |
5 | 1402231121200343 |
6 | 41304040210045 |
7 | 4004365040450 |
oct | 635700103755 |
9 | 168338882132 |
10 | 55549396973 |
11 | 21616206144 |
12 | a923469925 |
13 | 531368a485 |
14 | 298d765497 |
15 | 16a1b708b8 |
hex | cef0087ed |
55549396973 has 4 divisors (see below), whose sum is σ = 63485025120. Its totient is φ = 47613768828.
The previous prime is 55549396921. The next prime is 55549396999. The reversal of 55549396973 is 37969394555.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55549396973 - 26 = 55549396909 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55549390973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3967814063 + ... + 3967814076.
It is an arithmetic number, because the mean of its divisors is an integer number (15871256280).
Almost surely, 255549396973 is an apocalyptic number.
It is an amenable number.
55549396973 is a deficient number, since it is larger than the sum of its proper divisors (7935628147).
55549396973 is an equidigital number, since it uses as much as digits as its factorization.
55549396973 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7935628146.
The product of its digits is 137781000, while the sum is 65.
The spelling of 55549396973 in words is "fifty-five billion, five hundred forty-nine million, three hundred ninety-six thousand, nine hundred seventy-three".
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