Base | Representation |
---|---|
bin | 11001010000110011110010… |
… | …00000000100001001101011 |
3 | 21021200211100122020202210101 |
4 | 30220121321000010021223 |
5 | 24240140311042112403 |
6 | 314052431524530231 |
7 | 14462403344603311 |
oct | 1450317100041153 |
9 | 237624318222711 |
10 | 55553137066603 |
11 | 16778a53674720 |
12 | 62926a1250977 |
13 | 24cc83b5aa347 |
14 | da0b013ca0b1 |
15 | 6650e7e7571d |
hex | 32867900426b |
55553137066603 has 8 divisors (see below), whose sum is σ = 60907962067200. Its totient is φ = 50249068701480.
The previous prime is 55553137066589. The next prime is 55553137066631. The reversal of 55553137066603 is 30666073135555.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55553137066603 - 25 = 55553137066571 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55553137066663) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12689156575 + ... + 12689160952.
It is an arithmetic number, because the mean of its divisors is an integer number (7613495258400).
Almost surely, 255553137066603 is an apocalyptic number.
55553137066603 is a deficient number, since it is larger than the sum of its proper divisors (5354825000597).
55553137066603 is a wasteful number, since it uses less digits than its factorization.
55553137066603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25378317737.
The product of its (nonzero) digits is 25515000, while the sum is 55.
The spelling of 55553137066603 in words is "fifty-five trillion, five hundred fifty-three billion, one hundred thirty-seven million, sixty-six thousand, six hundred three".
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