Base | Representation |
---|---|
bin | 11001010101111111010011… |
… | …01111001000110011011011 |
3 | 21022022211202201111222100210 |
4 | 30222333221233020303123 |
5 | 24301044314230120010 |
6 | 314310305110102203 |
7 | 14511304105543314 |
oct | 1452775157106333 |
9 | 238284681458323 |
10 | 55731122113755 |
11 | 16837488586a10 |
12 | 630109404a963 |
13 | 25135649404aa |
14 | da958775760b |
15 | 669a63815b20 |
hex | 32afe9bc8cdb |
55731122113755 has 64 divisors (see below), whose sum is σ = 100894387055616. Its totient is φ = 26030543040000.
The previous prime is 55731122113741. The next prime is 55731122113769.
55731122113755 is nontrivially palindromic in base 10.
It is an interprime number because it is at equal distance from previous prime (55731122113741) and next prime (55731122113769).
It is not a de Polignac number, because 55731122113755 - 26 = 55731122113691 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 44575311 + ... + 45808520.
It is an arithmetic number, because the mean of its divisors is an integer number (1576474797744).
Almost surely, 255731122113755 is an apocalyptic number.
55731122113755 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55731122113755 is a deficient number, since it is larger than the sum of its proper divisors (45163264941861).
55731122113755 is a wasteful number, since it uses less digits than its factorization.
55731122113755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90383988.
The product of its digits is 1102500, while the sum is 48.
It can be divided in two parts, 5573112 and 2113755, that added together give a palindrome (7686867).
The spelling of 55731122113755 in words is "fifty-five trillion, seven hundred thirty-one billion, one hundred twenty-two million, one hundred thirteen thousand, seven hundred fifty-five".
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