Base | Representation |
---|---|
bin | 101000100100000101011… |
… | …1001111011100000001111 |
3 | 201201222011212002200110101 |
4 | 1101020022321323200033 |
5 | 1212320200412231203 |
6 | 15505050504351531 |
7 | 1113532643301253 |
oct | 121101271734017 |
9 | 21658155080411 |
10 | 5575050508303 |
11 | 185a402741731 |
12 | 7605951755a7 |
13 | 315956ac0b23 |
14 | 153b96270263 |
15 | 9a04704741d |
hex | 5120ae7b80f |
5575050508303 has 8 divisors (see below), whose sum is σ = 5819222578176. Its totient is φ = 5331026652600.
The previous prime is 5575050508253. The next prime is 5575050508309. The reversal of 5575050508303 is 3038050505755.
5575050508303 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5575050508303 - 233 = 5566460573711 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5575050508309) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36976663 + ... + 37127128.
It is an arithmetic number, because the mean of its divisors is an integer number (727402822272).
Almost surely, 25575050508303 is an apocalyptic number.
5575050508303 is a deficient number, since it is larger than the sum of its proper divisors (244172069873).
5575050508303 is a wasteful number, since it uses less digits than its factorization.
5575050508303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74107085.
The product of its (nonzero) digits is 1575000, while the sum is 46.
The spelling of 5575050508303 in words is "five trillion, five hundred seventy-five billion, fifty million, five hundred eight thousand, three hundred three".
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