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5575683003131 = 6897798083289
BaseRepresentation
bin101000100100011000010…
…0110101101001011111011
3201202000210221020202020202
41101020300212231023323
51212322444322100011
615505233341112415
71113554423356433
oct121106046551373
921660727222222
105575683003131
11185a6a777442a
12760730b5870b
13315a27b56117
14153c162752c3
159a08283323b
hex512309ad2fb

5575683003131 has 4 divisors (see below), whose sum is σ = 5575691776200. Its totient is φ = 5575674230064.

The previous prime is 5575683003061. The next prime is 5575683003157. The reversal of 5575683003131 is 1313003865755.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5575683003131 - 242 = 1177636492027 is a prime.

It is a super-2 number, since 2×55756830031312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5575683053131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3351866 + ... + 4731423.

It is an arithmetic number, because the mean of its divisors is an integer number (1393922944050).

Almost surely, 25575683003131 is an apocalyptic number.

5575683003131 is a deficient number, since it is larger than the sum of its proper divisors (8773069).

5575683003131 is an equidigital number, since it uses as much as digits as its factorization.

5575683003131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8773068.

The product of its (nonzero) digits is 1134000, while the sum is 47.

Adding to 5575683003131 its reverse (1313003865755), we get a palindrome (6888686868886).

The spelling of 5575683003131 in words is "five trillion, five hundred seventy-five billion, six hundred eighty-three million, three thousand, one hundred thirty-one".

Divisors: 1 689779 8083289 5575683003131