Base | Representation |
---|---|
bin | 11001010111110101001110… |
… | …11000101101111100011011 |
3 | 21022112220011222222002011002 |
4 | 30223322213120231330123 |
5 | 24303113444430343010 |
6 | 314355335303455215 |
7 | 14516005034165660 |
oct | 1453724730557433 |
9 | 238486158862132 |
10 | 55794433449755 |
11 | 168613171407a0 |
12 | 6311402a5750b |
13 | 251951441b6a0 |
14 | dac671cd7a67 |
15 | 66b51bb0a1a5 |
hex | 32bea762df1b |
55794433449755 has 64 divisors (see below), whose sum is σ = 89992140134400. Its totient is φ = 32070926315520.
The previous prime is 55794433449673. The next prime is 55794433449787.
55794433449755 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55794433449755 - 240 = 54694921821979 is a prime.
It is a super-2 number, since 2×557944334497552 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1350215 + ... + 10649504.
It is an arithmetic number, because the mean of its divisors is an integer number (1406127189600).
Almost surely, 255794433449755 is an apocalyptic number.
55794433449755 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55794433449755 is a deficient number, since it is larger than the sum of its proper divisors (34197706684645).
55794433449755 is a wasteful number, since it uses less digits than its factorization.
55794433449755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12000684.
The product of its digits is 5715360000, while the sum is 74.
The spelling of 55794433449755 in words is "fifty-five trillion, seven hundred ninety-four billion, four hundred thirty-three million, four hundred forty-nine thousand, seven hundred fifty-five".
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