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5580113183 = 12323452821
BaseRepresentation
bin1010011001001100…
…11100010100011111
3112101212222010020122
411030212130110133
542412002110213
62321413105155
7255165115361
oct51446342437
915355863218
105580113183
112403912697
1210b89281bb
136ac0b3728
143ad14cd31
15229d46d08
hex14c99c51f

5580113183 has 4 divisors (see below), whose sum is σ = 5580578328. Its totient is φ = 5579648040.

The previous prime is 5580113171. The next prime is 5580113207. The reversal of 5580113183 is 3813110855.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5580113183 - 28 = 5580112927 is a prime.

It is a super-3 number, since 3×55801131833 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5580113113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214088 + ... + 238733.

It is an arithmetic number, because the mean of its divisors is an integer number (1395144582).

Almost surely, 25580113183 is an apocalyptic number.

5580113183 is a deficient number, since it is larger than the sum of its proper divisors (465145).

5580113183 is a wasteful number, since it uses less digits than its factorization.

5580113183 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 465144.

The product of its (nonzero) digits is 14400, while the sum is 35.

The square root of 5580113183 is about 74700.1551738683. The cubic root of 5580113183 is about 1773.7034168537.

The spelling of 5580113183 in words is "five billion, five hundred eighty million, one hundred thirteen thousand, one hundred eighty-three".

Divisors: 1 12323 452821 5580113183