Base | Representation |
---|---|
bin | 110100000100110100… |
… | …111001011011100001 |
3 | 12100022211222021021100 |
4 | 310010310321123201 |
5 | 1404003340103213 |
6 | 41404240145013 |
7 | 4016432223321 |
oct | 640464713341 |
9 | 170284867240 |
10 | 55915550433 |
11 | 21793963706 |
12 | aa06008169 |
13 | 53714ab022 |
14 | 29c6239281 |
15 | 16c3d9a773 |
hex | d04d396e1 |
55915550433 has 96 divisors (see below), whose sum is σ = 88480828800. Its totient is φ = 33909580800.
The previous prime is 55915550407. The next prime is 55915550479. The reversal of 55915550433 is 33405551955.
55915550433 is a `hidden beast` number, since 5 + 5 + 91 + 5 + 550 + 4 + 3 + 3 = 666.
It is not a de Polignac number, because 55915550433 - 28 = 55915550177 is a prime.
It is not an unprimeable number, because it can be changed into a prime (55915550233) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 176389591 + ... + 176389907.
It is an arithmetic number, because the mean of its divisors is an integer number (921675300).
Almost surely, 255915550433 is an apocalyptic number.
It is an amenable number.
55915550433 is a deficient number, since it is larger than the sum of its proper divisors (32565278367).
55915550433 is a wasteful number, since it uses less digits than its factorization.
55915550433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 703 (or 700 counting only the distinct ones).
The product of its (nonzero) digits is 1012500, while the sum is 45.
The spelling of 55915550433 in words is "fifty-five billion, nine hundred fifteen million, five hundred fifty thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •