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5603134313065 = 51120626862613
BaseRepresentation
bin101000110001001010011…
…0101001001001001101001
3201211122200001201210010111
41101202110311021021221
51213300204341004230
615530013330014321
71115545614556132
oct121422465111151
921748601653114
105603134313065
111870304278933
12765b124173a1
133184b11a1993
1415529bdd6c89
159ab3c81492a
hex51894d49269

5603134313065 has 4 divisors (see below), whose sum is σ = 6723761175684. Its totient is φ = 4482507450448.

The previous prime is 5603134313017. The next prime is 5603134313081.

It is a happy number.

5603134313065 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2685586778176 + 2917547534889 = 1638776^2 + 1708083^2 .

It is a cyclic number.

It is not a de Polignac number, because 5603134313065 - 221 = 5603132215913 is a prime.

It is a super-2 number, since 2×56031343130652 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 560313431302 + ... + 560313431311.

It is an arithmetic number, because the mean of its divisors is an integer number (1680940293921).

Almost surely, 25603134313065 is an apocalyptic number.

It is an amenable number.

5603134313065 is a deficient number, since it is larger than the sum of its proper divisors (1120626862619).

5603134313065 is a wasteful number, since it uses less digits than its factorization.

5603134313065 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1120626862618.

The product of its (nonzero) digits is 291600, while the sum is 40.

The spelling of 5603134313065 in words is "five trillion, six hundred three billion, one hundred thirty-four million, three hundred thirteen thousand, sixty-five".

Divisors: 1 5 1120626862613 5603134313065