Base | Representation |
---|---|
bin | 101000110001001010011… |
… | …0101001001001001101001 |
3 | 201211122200001201210010111 |
4 | 1101202110311021021221 |
5 | 1213300204341004230 |
6 | 15530013330014321 |
7 | 1115545614556132 |
oct | 121422465111151 |
9 | 21748601653114 |
10 | 5603134313065 |
11 | 1870304278933 |
12 | 765b124173a1 |
13 | 3184b11a1993 |
14 | 15529bdd6c89 |
15 | 9ab3c81492a |
hex | 51894d49269 |
5603134313065 has 4 divisors (see below), whose sum is σ = 6723761175684. Its totient is φ = 4482507450448.
The previous prime is 5603134313017. The next prime is 5603134313081.
It is a happy number.
5603134313065 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2685586778176 + 2917547534889 = 1638776^2 + 1708083^2 .
It is a cyclic number.
It is not a de Polignac number, because 5603134313065 - 221 = 5603132215913 is a prime.
It is a super-2 number, since 2×56031343130652 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 560313431302 + ... + 560313431311.
It is an arithmetic number, because the mean of its divisors is an integer number (1680940293921).
Almost surely, 25603134313065 is an apocalyptic number.
It is an amenable number.
5603134313065 is a deficient number, since it is larger than the sum of its proper divisors (1120626862619).
5603134313065 is a wasteful number, since it uses less digits than its factorization.
5603134313065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1120626862618.
The product of its (nonzero) digits is 291600, while the sum is 40.
The spelling of 5603134313065 in words is "five trillion, six hundred three billion, one hundred thirty-four million, three hundred thirteen thousand, sixty-five".
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