Base | Representation |
---|---|
bin | 11001011111010101100100… |
… | …10110110111011111010111 |
3 | 21100110112211020122012110010 |
4 | 30233222302112313133113 |
5 | 24321330120240123303 |
6 | 315114024524131303 |
7 | 14543434426660542 |
oct | 1457526226673727 |
9 | 240415736565403 |
10 | 56052315551703 |
11 | 16950720936889 |
12 | 6353393096b33 |
13 | 2537931481413 |
14 | dbad37483859 |
15 | 6730b18d1c03 |
hex | 32fab25b77d7 |
56052315551703 has 8 divisors (see below), whose sum is σ = 75062780652400. Its totient is φ = 37205030409408.
The previous prime is 56052315551623. The next prime is 56052315551707. The reversal of 56052315551703 is 30715551325065.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 56052315551703 - 220 = 56052314503127 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56052315551707) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40794988798 + ... + 40794990171.
It is an arithmetic number, because the mean of its divisors is an integer number (9382847581550).
Almost surely, 256052315551703 is an apocalyptic number.
56052315551703 is a deficient number, since it is larger than the sum of its proper divisors (19010465100697).
56052315551703 is a wasteful number, since it uses less digits than its factorization.
56052315551703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81589979201.
The product of its (nonzero) digits is 2362500, while the sum is 48.
Adding to 56052315551703 its reverse (30715551325065), we get a palindrome (86767866876768).
The spelling of 56052315551703 in words is "fifty-six trillion, fifty-two billion, three hundred fifteen million, five hundred fifty-one thousand, seven hundred three".
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