Base | Representation |
---|---|
bin | 10000010100111100100… |
… | …01100101110011011111 |
3 | 1222122001010122201012011 |
4 | 20022132101211303133 |
5 | 33142412244104103 |
6 | 1105415333452051 |
7 | 55350063115522 |
oct | 10123621456337 |
9 | 1878033581164 |
10 | 561001159903 |
11 | 1a6a12590838 |
12 | 908861a1027 |
13 | 40b96130072 |
14 | 1d21ca46bb9 |
15 | e8d61e5d6d |
hex | 829e465cdf |
561001159903 has 4 divisors (see below), whose sum is σ = 590527536760. Its totient is φ = 531474783048.
The previous prime is 561001159897. The next prime is 561001159921. The reversal of 561001159903 is 309951100165.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 561001159903 - 217 = 561001028831 is a prime.
It is a super-2 number, since 2×5610011599032 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (561001159933) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14763188400 + ... + 14763188437.
It is an arithmetic number, because the mean of its divisors is an integer number (147631884190).
Almost surely, 2561001159903 is an apocalyptic number.
561001159903 is a deficient number, since it is larger than the sum of its proper divisors (29526376857).
561001159903 is a wasteful number, since it uses less digits than its factorization.
561001159903 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29526376856.
The product of its (nonzero) digits is 36450, while the sum is 40.
The spelling of 561001159903 in words is "five hundred sixty-one billion, one million, one hundred fifty-nine thousand, nine hundred three".
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