Base | Representation |
---|---|
bin | 111111110010110011011000… |
… | …1010000110100111010111001 |
3 | 2201120211002111112100220010002 |
4 | 1333211212301100310322321 |
5 | 1042022123321443432101 |
6 | 5305234220315202345 |
7 | 226123515024636140 |
oct | 17745466120647271 |
9 | 2646732445326102 |
10 | 561136156233401 |
11 | 15288256444a1a1 |
12 | 52b27b434463b5 |
13 | 1b114bb2950498 |
14 | 9c7d1c6142757 |
15 | 44d168c274d6b |
hex | 1fe59b1434eb9 |
561136156233401 has 4 divisors (see below), whose sum is σ = 641298464266752. Its totient is φ = 480973848200052.
The previous prime is 561136156233397. The next prime is 561136156233427. The reversal of 561136156233401 is 104332651631165.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 561136156233401 - 22 = 561136156233397 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (561136156233491) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40081154016665 + ... + 40081154016678.
It is an arithmetic number, because the mean of its divisors is an integer number (160324616066688).
Almost surely, 2561136156233401 is an apocalyptic number.
It is an amenable number.
561136156233401 is a deficient number, since it is larger than the sum of its proper divisors (80162308033351).
561136156233401 is an equidigital number, since it uses as much as digits as its factorization.
561136156233401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80162308033350.
The product of its (nonzero) digits is 1166400, while the sum is 47.
The spelling of 561136156233401 in words is "five hundred sixty-one trillion, one hundred thirty-six billion, one hundred fifty-six million, two hundred thirty-three thousand, four hundred one".
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