Base | Representation |
---|---|
bin | 100001011101001… |
… | …101011000011001 |
3 | 1110010012020212021 |
4 | 201131031120121 |
5 | 2122143230423 |
6 | 131410414441 |
7 | 16624005025 |
oct | 4135153031 |
9 | 1403166767 |
10 | 561305113 |
11 | 268929926 |
12 | 137b91421 |
13 | 8c39b105 |
14 | 54793385 |
15 | 3442795d |
hex | 2174d619 |
561305113 has 4 divisors (see below), whose sum is σ = 561924880. Its totient is φ = 560685348.
The previous prime is 561305093. The next prime is 561305117. The reversal of 561305113 is 311503165.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311503165 = 5 ⋅62300633.
It is a cyclic number.
It is not a de Polignac number, because 561305113 - 213 = 561296921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (561305117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 308523 + ... + 310336.
It is an arithmetic number, because the mean of its divisors is an integer number (140481220).
Almost surely, 2561305113 is an apocalyptic number.
It is an amenable number.
561305113 is a deficient number, since it is larger than the sum of its proper divisors (619767).
561305113 is an equidigital number, since it uses as much as digits as its factorization.
561305113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 619766.
The product of its (nonzero) digits is 1350, while the sum is 25.
The square root of 561305113 is about 23691.8786296064. The cubic root of 561305113 is about 824.8968897154.
Adding to 561305113 its reverse (311503165), we get a palindrome (872808278).
The spelling of 561305113 in words is "five hundred sixty-one million, three hundred five thousand, one hundred thirteen".
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