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564040264413 = 3188013421471
BaseRepresentation
bin10000011010100110110…
…10110110101011011101
31222220212221021012211110
420031103122312223131
533220123301430123
61111041100212233
755515305066523
oct10152332665335
91886787235743
10564040264413
111a823202aa5a
1291393b3a079
134125b956662
141d42a50c313
15ea12e11493
hex83536b6add

564040264413 has 4 divisors (see below), whose sum is σ = 752053685888. Its totient is φ = 376026842940.

The previous prime is 564040264397. The next prime is 564040264451. The reversal of 564040264413 is 314462040465.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 564040264413 - 24 = 564040264397 is a prime.

It is a super-3 number, since 3×5640402644133 (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (564040264013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94006710733 + ... + 94006710738.

It is an arithmetic number, because the mean of its divisors is an integer number (188013421472).

Almost surely, 2564040264413 is an apocalyptic number.

It is an amenable number.

564040264413 is a deficient number, since it is larger than the sum of its proper divisors (188013421475).

564040264413 is a wasteful number, since it uses less digits than its factorization.

564040264413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188013421474.

The product of its (nonzero) digits is 276480, while the sum is 39.

The spelling of 564040264413 in words is "five hundred sixty-four billion, forty million, two hundred sixty-four thousand, four hundred thirteen".

Divisors: 1 3 188013421471 564040264413