Base | Representation |
---|---|
bin | 110100100011011111… |
… | …101101110010101001 |
3 | 12101122201011122211102 |
4 | 310203133231302221 |
5 | 1411032100411213 |
6 | 41531300411145 |
7 | 4035250602002 |
oct | 644337556251 |
9 | 171581148742 |
10 | 56430091433 |
11 | 21a28351a01 |
12 | ab2a3a6ab5 |
13 | 5423c84861 |
14 | 2a346d81a9 |
15 | 1704137158 |
hex | d237edca9 |
56430091433 has 4 divisors (see below), whose sum is σ = 56456206548. Its totient is φ = 56403976320.
The previous prime is 56430091427. The next prime is 56430091453. The reversal of 56430091433 is 33419003465.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 11979959209 + 44450132224 = 109453^2 + 210832^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56430091433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (56430091453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13054316 + ... + 13058637.
It is an arithmetic number, because the mean of its divisors is an integer number (14114051637).
Almost surely, 256430091433 is an apocalyptic number.
It is an amenable number.
56430091433 is a deficient number, since it is larger than the sum of its proper divisors (26115115).
56430091433 is a wasteful number, since it uses less digits than its factorization.
56430091433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26115114.
The product of its (nonzero) digits is 116640, while the sum is 38.
Adding to 56430091433 its reverse (33419003465), we get a palindrome (89849094898).
The spelling of 56430091433 in words is "fifty-six billion, four hundred thirty million, ninety-one thousand, four hundred thirty-three".
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