Base | Representation |
---|---|
bin | 1000000001001111011011111… |
… | …0000010101000000001011111 |
3 | 2202000001221201222101210010211 |
4 | 2000103312332002220001133 |
5 | 1042431212343440212112 |
6 | 5320110323014513251 |
7 | 226602250001455621 |
oct | 20023667602500137 |
9 | 2660057658353124 |
10 | 564314646413407 |
11 | 15389855227aa2a |
12 | 5335bb61365827 |
13 | 1b2b58483749c6 |
14 | 9d4cd904d6c11 |
15 | 45391bb8880a7 |
hex | 2013dbe0a805f |
564314646413407 has 4 divisors (see below), whose sum is σ = 564318025366096. Its totient is φ = 564311267460720.
The previous prime is 564314646413363. The next prime is 564314646413411. The reversal of 564314646413407 is 704314646413465.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-564314646413407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (564314646213407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1689225819 + ... + 1689559852.
It is an arithmetic number, because the mean of its divisors is an integer number (141079506341524).
Almost surely, 2564314646413407 is an apocalyptic number.
564314646413407 is a deficient number, since it is larger than the sum of its proper divisors (3378952689).
564314646413407 is a wasteful number, since it uses less digits than its factorization.
564314646413407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3378952688.
The product of its (nonzero) digits is 69672960, while the sum is 58.
Adding to 564314646413407 its sum of digits (58), we get a palindrome (564314646413465).
The spelling of 564314646413407 in words is "five hundred sixty-four trillion, three hundred fourteen billion, six hundred forty-six million, four hundred thirteen thousand, four hundred seven".
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