Base | Representation |
---|---|
bin | 110100100111011100… |
… | …111011110001011011 |
3 | 12101211100002002122202 |
4 | 310213130323301123 |
5 | 1411201044034011 |
6 | 41542031240415 |
7 | 4040015036552 |
oct | 644734736133 |
9 | 171740062582 |
10 | 56496471131 |
11 | 21a6186aa61 |
12 | ab4867910b |
13 | 5434956599 |
14 | 2a3d456d99 |
15 | 1709d9a23b |
hex | d2773bc5b |
56496471131 has 4 divisors (see below), whose sum is σ = 56497629264. Its totient is φ = 56495313000.
The previous prime is 56496471089. The next prime is 56496471217. The reversal of 56496471131 is 13117469465.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 56496471131 - 26 = 56496471067 is a prime.
It is a super-2 number, since 2×564964711312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (56496491131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502520 + ... + 604581.
It is an arithmetic number, because the mean of its divisors is an integer number (14124407316).
Almost surely, 256496471131 is an apocalyptic number.
56496471131 is a deficient number, since it is larger than the sum of its proper divisors (1158133).
56496471131 is a wasteful number, since it uses less digits than its factorization.
56496471131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1158132.
The product of its digits is 544320, while the sum is 47.
The spelling of 56496471131 in words is "fifty-six billion, four hundred ninety-six million, four hundred seventy-one thousand, one hundred thirty-one".
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