Base | Representation |
---|---|
bin | 11001101101111110011000… |
… | …00000011110011110100101 |
3 | 21102020122000002211012001211 |
4 | 30312333030000132132211 |
5 | 24403100131302011313 |
6 | 320141043150151421 |
7 | 14624660664202660 |
oct | 1466771400363645 |
9 | 242218002735054 |
10 | 56555257063333 |
11 | 17024a4a246526 |
12 | 64149551b2571 |
13 | 25731a3b45802 |
14 | dd74092066d7 |
15 | 6811ea8a3e3d |
hex | 336fcc01e7a5 |
56555257063333 has 4 divisors (see below), whose sum is σ = 64634579500960. Its totient is φ = 48475934625708.
The previous prime is 56555257063303. The next prime is 56555257063339. The reversal of 56555257063333 is 33336075255565.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 56555257063333 - 241 = 54356233807781 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56555257063339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4039661218803 + ... + 4039661218816.
It is an arithmetic number, because the mean of its divisors is an integer number (16158644875240).
Almost surely, 256555257063333 is an apocalyptic number.
It is an amenable number.
56555257063333 is a deficient number, since it is larger than the sum of its proper divisors (8079322437627).
56555257063333 is an equidigital number, since it uses as much as digits as its factorization.
56555257063333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8079322437626.
The product of its (nonzero) digits is 127575000, while the sum is 58.
The spelling of 56555257063333 in words is "fifty-six trillion, five hundred fifty-five billion, two hundred fifty-seven million, sixty-three thousand, three hundred thirty-three".
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