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56555262143317 = 721154189023333
BaseRepresentation
bin11001101101111110011000…
…10011110110101101010101
321102020122000110101021111101
430312333030103312231111
524403100134102041232
6320141043451110101
714624661055321300
oct1466771423665525
9242218013337441
1056555262143317
1117024a520a6163
126414956a42331
1325731a4c03b12
14dd7409b69b37
156811eb0591e7
hex336fcc4f6b55

56555262143317 has 6 divisors (see below), whose sum is σ = 65788774330038. Its totient is φ = 48475938979944.

The previous prime is 56555262143297. The next prime is 56555262143389. The reversal of 56555262143317 is 71334126255565.

It can be written as a sum of positive squares in only one way, i.e., 49119436692676 + 7435825450641 = 7008526^2 + 2726871^2 .

It is a de Polignac number, because none of the positive numbers 2k-56555262143317 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (56555262543317) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 577094511618 + ... + 577094511715.

It is an arithmetic number, because the mean of its divisors is an integer number (10964795721673).

Almost surely, 256555262143317 is an apocalyptic number.

It is an amenable number.

56555262143317 is a deficient number, since it is larger than the sum of its proper divisors (9233512186721).

56555262143317 is a wasteful number, since it uses less digits than its factorization.

56555262143317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1154189023347 (or 1154189023340 counting only the distinct ones).

The product of its digits is 22680000, while the sum is 55.

The spelling of 56555262143317 in words is "fifty-six trillion, five hundred fifty-five billion, two hundred sixty-two million, one hundred forty-three thousand, three hundred seventeen".

Divisors: 1 7 49 1154189023333 8079323163331 56555262143317