Base | Representation |
---|---|
bin | 11001101101111110011000… |
… | …10011110110101101010101 |
3 | 21102020122000110101021111101 |
4 | 30312333030103312231111 |
5 | 24403100134102041232 |
6 | 320141043451110101 |
7 | 14624661055321300 |
oct | 1466771423665525 |
9 | 242218013337441 |
10 | 56555262143317 |
11 | 17024a520a6163 |
12 | 6414956a42331 |
13 | 25731a4c03b12 |
14 | dd7409b69b37 |
15 | 6811eb0591e7 |
hex | 336fcc4f6b55 |
56555262143317 has 6 divisors (see below), whose sum is σ = 65788774330038. Its totient is φ = 48475938979944.
The previous prime is 56555262143297. The next prime is 56555262143389. The reversal of 56555262143317 is 71334126255565.
It can be written as a sum of positive squares in only one way, i.e., 49119436692676 + 7435825450641 = 7008526^2 + 2726871^2 .
It is a de Polignac number, because none of the positive numbers 2k-56555262143317 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56555262543317) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 577094511618 + ... + 577094511715.
It is an arithmetic number, because the mean of its divisors is an integer number (10964795721673).
Almost surely, 256555262143317 is an apocalyptic number.
It is an amenable number.
56555262143317 is a deficient number, since it is larger than the sum of its proper divisors (9233512186721).
56555262143317 is a wasteful number, since it uses less digits than its factorization.
56555262143317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1154189023347 (or 1154189023340 counting only the distinct ones).
The product of its digits is 22680000, while the sum is 55.
The spelling of 56555262143317 in words is "fifty-six trillion, five hundred fifty-five billion, two hundred sixty-two million, one hundred forty-three thousand, three hundred seventeen".
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