Base | Representation |
---|---|
bin | 1010101000110101… |
… | …11101001110111101 |
3 | 112202000212010011021 |
4 | 11110122331032331 |
5 | 43144044214442 |
6 | 2342421224141 |
7 | 261350263465 |
oct | 52432751675 |
9 | 15660763137 |
10 | 5711319997 |
11 | 2470989279 |
12 | 1134862051 |
13 | 7003325b6 |
14 | 3c2744ba5 |
15 | 236612e67 |
hex | 1546bd3bd |
5711319997 has 4 divisors (see below), whose sum is σ = 5719176736. Its totient is φ = 5703463260.
The previous prime is 5711319989. The next prime is 5711320019. The reversal of 5711319997 is 7999131175.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5711319997 - 23 = 5711319989 is a prime.
It is a super-2 number, since 2×57113199972 = 65238352216264160018, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5711319197) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3927279 + ... + 3928732.
It is an arithmetic number, because the mean of its divisors is an integer number (1429794184).
Almost surely, 25711319997 is an apocalyptic number.
It is an amenable number.
5711319997 is a deficient number, since it is larger than the sum of its proper divisors (7856739).
5711319997 is an equidigital number, since it uses as much as digits as its factorization.
5711319997 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7856738.
The product of its digits is 535815, while the sum is 52.
The square root of 5711319997 is about 75573.2756799651. The cubic root of 5711319997 is about 1787.4977257343.
The spelling of 5711319997 in words is "five billion, seven hundred eleven million, three hundred nineteen thousand, nine hundred ninety-seven".
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