Base | Representation |
---|---|
bin | 110101001101010000… |
… | …011111100000100011 |
3 | 12110110112120111020200 |
4 | 311031100133200203 |
5 | 1414000432300333 |
6 | 42125010040243 |
7 | 4061516211255 |
oct | 651520374043 |
9 | 173415514220 |
10 | 57130743843 |
11 | 222578a7488 |
12 | b0a4b79083 |
13 | 5506191b94 |
14 | 2a9d7a1cd5 |
15 | 17458d7c13 |
hex | d4d41f823 |
57130743843 has 24 divisors (see below), whose sum is σ = 83199986688. Its totient is φ = 37775298672.
The previous prime is 57130743797. The next prime is 57130743853. The reversal of 57130743843 is 34834703175.
57130743843 is a `hidden beast` number, since 571 + 3 + 0 + 7 + 4 + 38 + 43 = 666.
It is not a de Polignac number, because 57130743843 - 29 = 57130743331 is a prime.
It is not an unprimeable number, because it can be changed into a prime (57130743853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 674446 + ... + 754412.
It is an arithmetic number, because the mean of its divisors is an integer number (3466666112).
Almost surely, 257130743843 is an apocalyptic number.
57130743843 is a deficient number, since it is larger than the sum of its proper divisors (26069242845).
57130743843 is a wasteful number, since it uses less digits than its factorization.
57130743843 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80623 (or 80620 counting only the distinct ones).
The product of its (nonzero) digits is 846720, while the sum is 45.
The spelling of 57130743843 in words is "fifty-seven billion, one hundred thirty million, seven hundred forty-three thousand, eight hundred forty-three".
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